python3实现SMTP发送邮件详细教程
(编辑:jimmy 日期: 2025/11/14 浏览:3 次 )
简介
Demo
import smtplib
from email.header import Header
from email.mime.text import MIMEText
# 第三方 SMTP 服务
mail_host = "smtp.163.com" # SMTP服务器
mail_user = "***" # 用户名
mail_pass = "***" # 授权密码,非登录密码
sender = ***@163.com' # 发件人邮箱(最好写全, 不然会失败)
receivers = [***@qq.com'] # 接收邮件,可设置为你的QQ邮箱或者其他邮箱
content = '我用Python'
title = '人生苦短' # 邮件主题
def sendEmail():
message = MIMEText(content, 'plain', 'utf-8') # 内容, 格式, 编码
message['From'] = "{}".format(sender)
message['To'] = ",".join(receivers)
message['Subject'] = title
try:
smtpObj = smtplib.SMTP_SSL(mail_host, 465) # 启用SSL发信, 端口一般是465
smtpObj.login(mail_user, mail_pass) # 登录验证
smtpObj.sendmail(sender, receivers, message.as_string()) # 发送
print("mail has been send successfully.")
except smtplib.SMTPException as e:
print(e)
def send_email2(SMTP_host, from_account, from_passwd, to_account, subject, content):
email_client = smtplib.SMTP(SMTP_host)
email_client.login(from_account, from_passwd)
# create msg
msg = MIMEText(content, 'plain', 'utf-8')
msg['Subject'] = Header(subject, 'utf-8') # subject
msg['From'] = from_account
msg['To'] = to_account
email_client.sendmail(from_account, to_account, msg.as_string())
email_client.quit()
if __name__ == '__main__':
sendEmail()
# receiver = '***'
# send_email2(mail_host, mail_user, mail_pass, receiver, title, content)
刚开始测试时,第一次发送邮件是成功的,但是后面再次测试时却出现了提示554,根据给出的网址查看错误代码
554 DT:SPM 发送的邮件内容包含了未被许可的信息,或被系统识别为垃圾邮件。请检查是否有用户发送病毒或者垃圾邮件。如下图所示:
针对该问题,究竟如何解决,会在下一篇博文中进行展开。若看到的朋友有好的解决方法,还请提出,在此感谢。
附 参考资料
附 电子书福利(免积分下载)
《Flask Web开发:基于Python的Web应用开发实战》
《Learning Python, 5th Edition》
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。
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