PHP使用in_array函数检查数组中是否存在某个值

bool in_array( mixed needle, array array [, bool strict] )

<"Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
 echo "Got Irix";
}
if (in_array("mac", $os)) {
 echo "Got mac";
}
"htmlcode">

<"美国","英国","法国","德国","意大利","西班牙","丹麦");
if (in_array("美国",$europe)) {
echo "True";
}
"htmlcode">

<"'12.4' found with strict check ";
}
if (in_array(1.13, $a, true)) {
 echo "1.13 found with strict check ";
}
"htmlcode">

<"'ph' was found ";
}
if (in_array(array('f', 'i'), $a)) {
 echo "'fi' was found ";
}
if (in_array('o', $a)) {
 echo "'o' was found ";
}
"htmlcode">

bool in_array(mixed $needle,array $haystack [, bool $strict = FALSE ])


在 haystack 中搜索 needle，如果没有设置 strict 则使用宽松的比较。
注：自php5.4以后。数组定义由array()换成了array[] 。
希望本文所述对大家的php程序设计有所帮助。

            
           
            上一篇：PHP判断IP并转跳到相应城市分站的方法

            下一篇：PHP+MYSQL实现用户的增删改查